(re)use of AS numbers in 6bone routing?

Yann-Ju Chu yjchui@ms.chttl.com.tw
Sat, 02 Oct 1999 10:43:10 +0800



Mario Lorenz wrote:
> 
> On Fri, 1 Oct 1999, you wrote on the 6bone list:
> 
> > You should be able to use private AS numbers to peer with your
> > upstream (me) and any downstreams with whom you might also peer.
> 
> Since I am looking into implementing BGP too, I got a fundamental question
> on this approach: If someone uses private ASNs in the 6bone to do BGP,
> what would happen if I inadvertedly choose to use the very same (private)
> ASN ? To do full BGP, this means that the ASN is announced, and hence has
> to be globally unique...
> 
> The problem here is that I dont have my own IPv4 based ASN, and I also
> wont want to use my providers ASN for BGP, since thats a major ISP, and if
> someone makes a mistake and leaks IPv6 announcemnts into IPv4, whole
> germany will be mad at me.
> 
> Mario
> 
> --
> Mario Lorenz                           Internet: s96412@fh-telekom-leipzig.de
>                                        AX25:     DL5MLO@OK0PKL.#BOH.CZE.EU



The following is another record from 6Bone mail list
 ---------------------------------------
>       My question is that since a transit site usually have only one backbone
> site(as ISP) connected to 6Bone, should I apply for an ASN just for
> becoming an transit site? I have checked the 6Bone mail archive about
> the topic, but the old discussing seems to be about the ASN in
> provider-based address, not the ASN in BGP4+.
>       Can anyone answer my question? Thanks a lot.

You should be able to use private AS numbers to peer with your
upstream (me) and any downstreams with whom you might also peer
-----------------------------------------------


In my opinion, I guess it is only required that the ASNs among your upstream and downstream
are unique. Because after the aggregation, when your upstreams change BGP4+ routing information,
there are no your ASN in the information.

But the above is only what I quess. Hope there is other opinion about this.
                                        Chu